Hello. I need some help There is a code, which is made by two letters from 23 letters and 3 numbers from numbers 2,3,4. This code doesnt exist, when all three numbers in a code are the same. How many ways a code can be made. How I think: The letters can be: 23*23=529 Numbers: 3*3*2=18 But the answer is 12144. Can anyone help me?
Omg! I have forgotten to say that there is made of 5signs
i thought we have "26" alphabets
Yeah
Well, it is how the problem sounds. We can take any number, I need a way how to solve this problem
and, actually, I am NOT from USA/UK and our language doesnt have Q,W,X so it is why 23:))
so, any tips?
two letters from 23 = 23*22 3 letters = 3*2*1 = 6
how many signs you need in the code?
5
"5" available and you use how many of them?
and why it is 3*2*1 if it can be two same numbers?
all of them
yes. the order.. you can arrange them in 6 ways
impossible.. all "5" signs? your answer uses one of "4" signs
if "5" is correct, then the answer will not end with a "4" at its units place.
why it is not 3*3*2? :) You can use TWO same numbers, but you cant use three same numbers. For example: You CAN use a code like this AB 233, but you CANT use a code AB 333
could you post the exact wordings of the question.
so, it is then alphabets = 23*22 numbers = 3^3-3 = 24 total combinations = 23*22*24
Can you explain me?
alphabets = no repetition = 23*22 kapeesh?
number of ways of arranging all "3" numbers = 3^3 but no repetition -> so -> 3^3-3
well, the problem doesnt say letters cannot repeat:) But the answer is correct, thank you.
I know. and the signs are unacconted for too. but this is the only way I can explain that number you gave as the answer!
oh,okay:) Thank you.
yer welcome :D
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