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Mathematics 15 Online
OpenStudy (anonymous):

Finding interval for area inside one loop of the lemniscate.

OpenStudy (anonymous):

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OpenStudy (anonymous):

i am not sure how to find the interval of the integral, 0 to pi/2 does not work( times 2), 0 to pi does not work

OpenStudy (turingtest):

think about an interval for t where cos(t) ranges from 0 to 0

OpenStudy (turingtest):

at what values of t is cos 0 ?

OpenStudy (anonymous):

pi/2 and 3pi/2

OpenStudy (turingtest):

yes, but in that interval cos is negative try another

OpenStudy (anonymous):

5pi/2

OpenStudy (turingtest):

right, or if you are allowed to use negative angles -pi/2 to pi/2

OpenStudy (anonymous):

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OpenStudy (anonymous):

or should i use -pi/2 to pi/2

OpenStudy (turingtest):

-pi/2 to p/2 works, but think about the other possibility that I didn't hand you what is wrong with pi/2 to 5pi/2

OpenStudy (turingtest):

?

OpenStudy (anonymous):

who that make the integral 0?

OpenStudy (anonymous):

wont*

OpenStudy (anonymous):

|dw:1364838888272:dw|

OpenStudy (turingtest):

yeah, hmmm let me think for a sec funny I feel more comfortable with double integrals in polar than single

OpenStudy (anonymous):

sin is just ruining this problem

OpenStudy (turingtest):

I honestly have never seen a single integral in polar before do you have a source of info I can look at? all I can find online is double integral stuff...

OpenStudy (anonymous):

hmm, no it is just an example from my practice exam, the answer is 7/2 just no clue what the interval is

OpenStudy (turingtest):

ok found this http://en.wikibooks.org/wiki/Calculus/Polar_Integration

OpenStudy (turingtest):

I guess the logical thing to do is split the integral up into two and use absolute value

OpenStudy (anonymous):

|dw:1364839331073:dw|

OpenStudy (anonymous):

-pi to pi?

OpenStudy (turingtest):

but that would give us the other half of the lemniscate, and will also integrate to 0

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