Find the two products below. Compare and contrast, in complete sentences, the similarities and differences of the two. (x + 6)(x − 6) and (x − 6)(x − 6)
these are standard formulae..!!
But I don't get how to work it out. @Mashy
use the distributive property how would do (x+4)(3) = ?
3x+12 right? @Mashy
perfect.. now if you had (x+4)(x+3).. how would you do it?
It would be 2x+3x+4x+12?? @Mashy
Then you would simplify it?
not quite.. how did you get 2x?
oh wait it would be x^2 or just x?
you tell what is x times x ?
it would be x
what is 5 times 5 ?? is it 5? :P
its 25. ahhhh but I don't get it wouldn't x time x be x?? like 1 times 1?
but x can be anything... thats the meaning of a VARIABLE so we say in general x times x is x squared.. so if x = 5 then 5 times 5 = 5 squared = 25 and 1 times 1 = 1 squared =1 for 1 the answer is same because 1 times 1 is 1.. so that only holds good for 1 and nothing else get it? :) (or maybe zero :P)
oh okay! this is what I have so far for my question is this right? -6x+x^2-36+6x x^2-36 (answer) _________________________ 6x+x^2+36-6x x^2+36 (answer) Then we have to compare and contrast
first answer is perfect but second answer is wrong.. check properly do it again!
-6x+x^2+36-6x x^2-12x+36 Is that the right answer?
there you go.. thats right ;-)!
Okay, now all I need to do is the compare and contrast, but I have no idea how they are different. The only think I have is that the second equation -6x+x^2+36-6x x^2-12x+36 Comes out a perfect trinomial square. is that right?? @Mashy
hmm even i dunno what exactly is your question asking you ? when you say compare and contrast.. waht similarities do you see?? and what differences ?.. (a+b)^2 - is called as a trinomial square? i don't remember the terminologies!
Well the first equation only has a 2 part answer: x^2-36 But the second equation has a 3 part answer: x^2-12x+36 The 3 part answer had 2 negatives from the original equation, but the first one had a negative and positive. @mashy
well its true.. but i dunno if that is what is expected .. but everything you said is right :).
okay! thank you so much :) this really help! @Mashy
your welcome :P..
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