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Mathematics 18 Online
OpenStudy (anonymous):

Can a function with the complex roots 5, square root of 2, 3i be a fourth degree polynomial with rational coefficients?

OpenStudy (precal):

how many roots do this have? 5 roots?

OpenStudy (zehanz):

If 3i is a root, then -3i is also a root. So if the polynomial exists, is could be: \( (x-5)(x-\sqrt{2})(x-3i)(x+3i)\). Multiply it out so see if the coefficients are rational...

OpenStudy (zehanz):

(the √2 seems to be the problem here...)

OpenStudy (anonymous):

If all the coefficients are rational it means that it is a yes?

OpenStudy (zehanz):

Yes, so you now have to check that...

OpenStudy (anonymous):

thanks bro.

OpenStudy (zehanz):

YW!

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