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Can a function with the complex roots 5, square root of 2, 3i be a fourth degree polynomial with rational coefficients?
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how many roots do this have? 5 roots?
If 3i is a root, then -3i is also a root. So if the polynomial exists, is could be: \( (x-5)(x-\sqrt{2})(x-3i)(x+3i)\). Multiply it out so see if the coefficients are rational...
(the √2 seems to be the problem here...)
If all the coefficients are rational it means that it is a yes?
Yes, so you now have to check that...
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thanks bro.
YW!
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