Question

Evaluate the integral
(−43x) dx

Answer 1

\[\large \int\limits -43x\;dx \qquad = \qquad -43\int\limits x\;dx\]
We can pull the constant coefficient outside of the integral, it won't affect the process at all.



From here, use the `Power Rule for Integrals`\[\large \int\limits x^n\;dx \qquad = \qquad \frac{x^{n+1}}{n+1}+C\]

~Increase the power by 1
~Divide by this new power.

Answer 2

So it appears you have x^1

Understand how to proceed? :o

Answer 3

if I have x^1 would it just be 0?

Answer 4

No. With integrals, the power INCREASES, not decreases.

\[\large \int\limits x^1 \;dx \qquad = \qquad \frac{x^{1+1}}{1+1}\]Which we can write this way,\[\large \frac{1}{2}x^2\]

Answer 5

oh ok I understand now. I see what I did wrong.
Thank you