Question

what is the period of the function:

Answer 1

\[f(\theta)=-2\cos 3\theta \]

Answer 2

the standard form is : \(f(\theta)=A\cos (\omega t+\phi)=A\cos(2\pi t/T+\phi)\)
where T is the time period.
here, we get , \(\omega=2\pi/T = 3\)
can you find t from here ?

Answer 3

you lost me

Answer 4

i just compared cos \(3\theta\) with \(\cos \omega t\)
to get w=3
and time period T can be calculated from w= 2pi/T so,
\(2\pi /T=3\)
can't you find T from here ?

Answer 5

i dont think ive learned that yet

Answer 6

now you have ,
its really easy to get T from that equation....try once.

Answer 7

the only thing is i think my teacher wanted us to review idk if she'd be able to give me credit for that

Answer 8

omg i figured it out thank you though its all out of the unit circle!!

Answer 9

its the formula 2pi/b

Answer 10

... you used t and i got confused thank you so so much!

Answer 11

sorry for confusing you, i learned it that way,
and yes, its 2pi/b.
welcome :)

Answer 12

lol guess thats what one letter can do . but thank you so much any way