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Solve for x: (x – 4)2 = 2 A. x = 4 ± 2 B. x = 4 ± C. x = 4 ± D. x = 4 ± 2
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Is that 2 times x - 4?
No its \[(x - 4)^2 = 2\]
For choices B and C, it's 4 plus or minus....?
A. \[x = 4 ± 2\sqrt2 \] B. \[x = 4 ± \sqrt13\] C. \[x = 4 ± \sqrt2\] D. \[ x = 4 ± 2\sqrt13\] Sorry about the confusion
Well, to get rid of the squared, you have to take the square root on both sides.
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making the x's x^2 and taking the radical sign out from each equation, right?
Well, square rooting the left side would remove the exponent of 2 from the (x-4) and squaring rooting the right side would make the 2 into \[\sqrt{2}\]
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