Solve the following quadratic equation using the quadratic formula and then choose the correct solution set. 6x^2 - 7x + 2 = 0
First, we need to know the QF (quadratic formula).
That is \[X=-b \pm \sqrt{b ^{2}-4ac}\]
That is correct if you place it over (2a). I have the formula attached. For 6x^2 - 7x + 2 = 0. what are the values of a, b, and c?
A=6 B=7 C=2
Attached is how I set up QF problems to avoid sign problems.
A=6 B=7 -----------> This should be -7 C=2
so its set up like this \[-7\pm \sqrt{-7-4*6*2}\]
Here's what I have so far.
its that right
I don't think so.
ya me too
Under the radical, the b has to be squared: (-7)^2 = 49
I am writing the substitutions for a, b, and c, on the attached files. Have you seen my work?
ya
Look at this:
I think your formula was off a bit. Then, the substitution for a, b, and c was off. Writing all the steps takes time but I recommend it if you are having trouble with the problem.
@Shannon20150 We left off with x = 8/12 and x = 6/12. Those values will simplify to what?
8/12 = 2/? and 6/12 = 1/?
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