Question

Prove the converse of Lagrange's theorem for cyclic groups. i.e. The positive integer m, divisor of |G| (G is a finite cyclic group) is a subgroup of G of order m.

Any help appreciated!

Answer 1

huh

Answer 2

Do you need more info?

Answer 3

I should I wrote:
Show that a finite cyclic group of order n has a subgroup of order m for each positive integer m which divides n.