Question

Can someone help me with this question?

Answer 1

thanks

Answer 2

Looks like f(x) is an upside down parabola shifted UP by 2. Do you know what function represents a parabola. HINT: It's 'x' raised to some power. HINT2: It's shifted UP by 2. Up means positive.

Answer 3

y = f(x) ?

Answer 4

is it just shifted down by 2, and to the right by 3?

Answer 5

or are we expanding and compressing as well?

Answer 6

we're expanding vertically by a factor of 2?

Answer 7

if you give me the answer, and I'll analyze what you did.

Answer 8

because I'm really confused, and at this point it'll be more productive if you can just see what you've done.

Answer 9

*I

Answer 10

omfg!!!! \(f(x) = -x^2+2\)

Answer 11

At this point, I probably seem like a f**king idiot, but how do i sketch that out?

Answer 12

It's already been graphed for you!! It's asking you to find -2f(3x). Which means you plug in (3x) for "x" and then graph the result. What do you get when you plug in 3x????

Answer 13

a horizontal compression by a factor of 3?

Answer 14

Agh, sorry, I meant: \(-2((-3x)^2+2)\)

Answer 15

Now what's your new function?

Answer 16

\(6x^2-4\), which means your parabola is NO LONGER negative, meaning that it's not upside down, it's upward. And now it's shifted DOWN, by 4, instead of shifted up by 2 like it was previously.

Answer 17

Now, can you graph the new function?!

Answer 18

If \(-x^2\) is an upside down parabola, then \(x^2\) looks like how? And remember to shift it DOWN by 4.

Answer 19

so it's just the exact same parabola as previously graphed, but vertically flipped, and shifted down by 4?

Answer 20

wow, simple.

Answer 21

YES.

Answer 22

holy sh*t sorry about that. It's obvious to me now...

Answer 23

I'll rate you as best response, and would love if you could help me with another question I'll post. should be way easier this time.

Answer 24

i'll rate you best answer again

Answer 25

I highly suggest that you memorize the 4-6 basic graphs. I believe they are: \(x^2, x^3, \frac{ 1 }{ x }, \ln(x), e^x\) and I think \(\sqrt{x} = x^{\frac{ 1 }{ 2 }}\)

Answer 26

alrighty, thanks for that. new question coming right up