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Physics 7 Online
OpenStudy (anonymous):

***Help Request*** ***Fan AND Medal Rewarded to best answer*** The latent heat of fusion of alcohol is 25 kcal/kg and its melting point is -114oC. It has a specific heat of 0.60 in its liquid state. Calculate the energy needed to melt 2.0 kg of solid alcohol at -114oC and raise it to a temperature of -14oC.

OpenStudy (anonymous):

heat needed to melt from solid to liquid = latent heat of fusion/mass * mass = 25 Kcal/kg * 2kg = 50 Kcal ok, so now our frozen alcohol should be unfrozen... lets heat it up heat required to raise the temperature of liquid by (-14 -(-114)) i.e. 100 C i.e 373.15 K(kelvin) = 0.6 Kcal/Kg /K * 373.15 Kelvin * 2Kg = 447.78 Kcal Hence total heat required = 497.79 Kcal

OpenStudy (anonymous):

assuming the specific heat was of liquid alcohol was given as 0.6 cal per g per Kelvin which are the normal units

OpenStudy (anonymous):

Thank You for your help!!!!

OpenStudy (anonymous):

you're most welcome

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