Mathematics
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OpenStudy (anonymous):
Find the standard form of the equation of the ellipse and find the center. Given the vertices:(0,+-8); Foci: (0,+-4)
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OpenStudy (mertsj):
If the vertices are (0,8) and (0,-8), where is the center?
OpenStudy (anonymous):
(0,0)
OpenStudy (mertsj):
Exactly.
OpenStudy (mertsj):
And what is the value of "a"
OpenStudy (anonymous):
8?
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OpenStudy (mertsj):
yes. And do you know that the distance from the center to the focus is "c" ?
OpenStudy (anonymous):
yes
OpenStudy (mertsj):
So "c" is ???
OpenStudy (anonymous):
so you do c^2=a^2-b^2?
OpenStudy (mertsj):
yes
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OpenStudy (mertsj):
And remember that the major axis is vertical so a^2 goes under y^2
OpenStudy (anonymous):
but since the foci is given...c=-+2
OpenStudy (mertsj):
The focal point is (0,4) so c = 4
OpenStudy (anonymous):
oh you square the 2
OpenStudy (mertsj):
Where did you get 2?
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OpenStudy (anonymous):
so what goes under x^2?
OpenStudy (mertsj):
c is the distance from the center to the focal point. If the center is (0,0) and the focal point is (0,4), then c has to be 4
OpenStudy (anonymous):
oh ok
OpenStudy (mertsj):
16=64-b^2
-48=-b^2
48=b^2
OpenStudy (anonymous):
major axis is the same as vertices?
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OpenStudy (mertsj):
The major axis is the distance between the vertices and its length is 2a
OpenStudy (anonymous):
so b=sqrt48
OpenStudy (mertsj):
Yes.
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