How do I integrate this? (see first post for the integral)
\[\int\limits_{}^{}\frac{ \ln x }{ x^2 }dx\]
I think I can use substitution, but I'm not sure how...
Well, you CAN use substitution... you usually pick the logs anyway... let u = ln(x) :)
ok. so if u = ln x \[du = \frac{ 1 }{ x }dx\] and the integral is now \[\int\limits_{}^{}\frac{ u }{ x}du\] because I can only pull out one of the x's in the denominator how to I get rid of the other x? is it easier to solve this integral a different way?
Of course, you do this by parts :) But remember... \[\huge u=\ln(x) \rightarrow x=e^u\] AND \[\huge \frac{1}x=x^{-1}=(e^u)^{-1}=e^{-u}\] And that about sums it up, don't you think? ^.^
you could do one derivative by parts. then do a regular integration
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