Statistics Question (Confidence Intervals) It was found that x people in a sample of 225 supported a smoking ban in public places. If the 95% confidence interval for the proportion of people supporting the ban in the population from which the sample was taken is [0.2297,0.3481] calculate the value of x.
\[\frac{x}{225}-1.96\frac{\sigma}{\sqrt{225}}=0.2297\ ........(1)\] \[\frac{x}{225}+1.96\frac{\sigma}{\sqrt{225}}=0.3481\ ........(2)\] Adding equations (1) and (2) gives \[\frac{2x}{225}=0.5778\ .............(3)\] Now you just need to solve equation (3) to find the value of x
Oh, ok thanks! I did it similarly but wasn't sure it was the correct answer because they are giving you "an interval where x could be 95% of the time" so you can't be absolutely certain what x is....
The interval is where the population mean will occur in repeated samples 95% of the time. x is a specific number of people in a particular sample.
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