Question

What is the derfvative of (-sin x)

Answer 1

-cosx

Answer 2

So you wouldnt factor out the negative and then it would be the derivative of (-1)(sin x)???

Answer 3

the derivative of (-sin x) always gives -cosx????

Answer 4

no , since they are all in a bracket , derivative directly goes to -cosx

Answer 5

is that the same for like if you said the derivative of (-cos x) would be (-(-sinx)= sin x???

Answer 6

yes , then would be (-cosx)= sinx

Answer 7

www.wolframalpha.com check this one out ,might help you

Answer 8

or if you said the derivative of (-tanx)= (-(sec^2)x)
... BAsically since the negeitive is within the parinthesis then the derivative will be negative aswel?

Answer 9

look at this way , f'(3x)= 3
and f'(-3x)= 3

Answer 10

if you have the negative in the bracket , you need to count it at a same time, if it belongs to another part , so just let it be

Answer 11

I kind of get it but woulnt like f'(-3x)= -3 and not 3?

Answer 12

yea sorry , my bad , -3

Answer 13

f'(-3x)=-3

Answer 14

so basically with derivs of trig functions, the neg inside the brakets are just there. THey dont seem to have a purpose in solvin the equation. THats what is tripping me up