Question

http://oi46.tinypic.com/242wxav.jpg I know that from -infinity to -4 my graph will be negative but how do I graph that?

Answer 1

just plot
points
-∞
-4

Answer 2

@alienshe

What is the equation of the function you are graphing?
We need to know if the functions cuts the oblique asymptote.

Answer 3

\[R(x)=\frac{ x^2+2-12 }{ x-4 }\]

Answer 4

Is there an x missing on the +2 ?

Answer 5

So sorry! I'm mixing up my problems... \[R(x)= \frac{ x^2+x-12 }{ x-4 }\]

Answer 6

The oblique asymptote y = x + 5 does not pass through the origin. That's throwing off the graph sketching.

Answer 7

I thought the origin was (0,0)

Answer 8

The oblique asymptote should pass through (-5,0). The graph will come under that and intersect the x-axis at (-4,0).

Answer 9

The origin is (0,0).

y = x + 5
0 = 0 + 5 --> Not true. So, the line y = x + 5 does NOT pass through the origin.

Answer 10

Get an eraser and move the line y = x + 5 to where it is supposed to be. Then, we can trace the graph and move on to the next problem.

Answer 11

Check to see if you posted the correct work you did in the file you uploaded.

Answer 12

This is what I get. See what you think.
@alienshe

Answer 13

Does it have to pass through (0,5)?

Answer 14

Here's the answer that I got. Is it still okay?

Answer 15

The oblique asymptote y = x + 5 has to pass through (0,5) because it satisfies that equation. 5 = 0 + 5 so 5=5.

I am not saying that (0,5) is a point of the curve you are sketching.

Answer 16

You don't necessarily need those tic marks on graph. You can just call the point of intersection of the oblique asymptote and the y-axis the point (0,5).

Did you see my graph?

Answer 17

Yeah, I did. It was pretty helpful. Thanks.

Answer 18

Look at this.

Answer 19

I think I got it now. I want to spend more time on this and really understand it but I have other problems I need to move onto. Exam tomorrow :/ Thank you so much for helping me!

Answer 20

Alrighty. It gets easier.