Question

quadratic in vertex form
y=x^2-14x+53

Answer 1

do you know the steps for converting a quadratic to vertex form?

Answer 2

half of \(-14\) is \(-7\) so write it as
\[y=(x-7)^2+k\] so find \(k\) replace \(x\) by \(7\) in the original standard form, in other words
\[7^2-14\times 7+53=k\]

Answer 3

so when i am solving for x do i just forget about the 53

Answer 4

you are not "solving for \(x\)" the question was to write is "vertex form" i.e. to turn
\[y=x^2-14x+53\] in to \[y=(x-h)^2+k\]

Answer 5

i know but i am talking using x to get the y so i can get the vertex

Answer 6

\(h=\frac{b}{2a}\) which is this case is \(\frac{14}{2}=7\) so you start with
\[y=(x-7)^2+k\]

Answer 7

ok i get it

Answer 8

then you need \(k\) which is \[7^2-14\times 7+53=49-98+53=4\]

Answer 9

also i can show u another way to do it and its by factoring

Answer 10

final answer is
\[y=(x-7)^2+4\]

Answer 11

could i see the way by factoring