Question

Solve the triangle.

a = 12, b = 22, C = 95°

c ≈ 26, A ≈ 27.6°, B ≈ 57.4°

c ≈ 26, A ≈ 54.4°, B ≈ 30.6°

c ≈ 25.1, A ≈ 27.6°, B ≈ 57.4°

c ≈ 25.1, A ≈ 31.6°, B ≈ 53.4°

Answer 1

law of cosines for this one

Answer 2

\[c^2+a^2+b^2-2ab\cos(C)\] and a calculator

Answer 3

i don't get it

Answer 4

well that is because i made a mistake

Answer 5

\[c^2=a^2+b^2-2ab\cos(C)\] is what i meant to write

Answer 6

you need a calculator to compute \(c\)

Answer 7

ok c = 25.1 that leaves me with one of these two options how do i find the A or B
c ≈ 25.1, A ≈ 27.6°, B ≈ 57.4°

c ≈ 25.1, A ≈ 31.6°, B ≈ 53.4°

Answer 8

use the law of sines

Answer 9

\[\frac{\sin(A)}{a}=\frac{\sin(C)}{c}\]

Answer 10

you know three out of those four numbers, solve for \(A\)

Answer 11

\[\frac{ \sin A }{ 12 } = \frac{ \sin (95) }{ 25.1 }\]

Answer 12

\[\frac{ Sin A (12) }{ 12 } = \frac{ \sin 95 (12)}{ 25.1 } \]
\frac{ Sin A }{ 12 } = \frac{ 11.95 }{ 25.1 }
Sin A= 0.48 ??

Answer 13

approximately, yes

Answer 14

so \(A=\sin^{-1}(.48)\)

Answer 15

28.69 ??

Answer 16

i am getting 57 maybe i am doing something wrong

Answer 17

for one thing, i am getting \(25.5\) for \(c\) maybe i have the numbers wrong

Answer 18

ohhh

Answer 19

i see, \(c=26\)
http://www.wolframalpha.com/input/?i=sqrt%2812^2%2B22^2-2*12*22*cos%2895%29%29

Answer 20

then
\[\frac{ \sin A }{ 12 } = \frac{ \sin (95) }{ 26
}\]

Answer 21

0.46?

Answer 22

yes that is what i am getting

Answer 23

then \(A=\sin^{-1}(.46)\)

Answer 24

27.39

Answer 25

http://www.wolframalpha.com/input/?i=arcsine%28+ \frac{+12\sin+%2895%29+}{+26++}%29

Answer 26

yes, go with that one

Answer 27

ok thank you so much! :)