What's an equation of the line with a slope of -5 and a y-intercept of (0,3)
the "slope intercept" form is \[y=mx+b\] in your case \(m=-5,b=3\)
put them directly in to the formula to get your answer okay with this?
What does x represent in this equation?
\(x\) is a variable there is an \(x\) in your answer
just like before when you had to find the range of \(y=3x-2\) for different values of \(x\) the \(x\) can be any number
in this case if you put \(m=-5\) and \(b=3\) you get a similar equation \[y=-5x+3\]
so for example if \(x=2\) you would get \(y=-5\times 2+3=-10+3=-7\) telling you that te point \((2,-7)\) is on the graph
@satellite73 What if my problem is like this.... Write the equation of the line passing through the points (0, -4) and (-2, 2).
then you have to find the slope first
\[m=\frac{-4-2}{0-(-2)}=\frac{-6}{2}=-3\]
now you already have the \(y\) intercept is \(-4\) because you are told \((0,-4)\) is on the graph
use \[y=mx+b\] with \(m=-3,b=-4\)
y=-3x-4
yes
I think I got the hang of this... once again thank you so much @satellite73. You've been the best!
you are quite welcome
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