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If functions f and g have domains Df and Dg respectively, then the domain of f / g is given by (A) the union of Df and Dg (B) the intersection of Df and Dg (C) the intersection of Df and Dg without the zeros of function g (D) None of the above
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Im going w/ C.) is tht correct?
yes it is think of it like this
if it was a union of the two sets, then you could plug in a value that would be in Df, but may not be in Dg the domain of f/g must be \(\large Df \cap Dg\) to make sure that any x value you plug in is acceptable for both functions also you can't divide by zero, so that's why you had to make sure g is nonzero
kk Thanks I appreciate it :))
np
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ahh bro @jim_thompson5910 is THE BEST :)
Haha ya he is lol :)
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