Question

Could someone check my answer
Solve the equation: 1/3x+9-2/x+3=2
x=-23/6
x=-3.833
so I thought that x=0,-2

Answer 1

\[\frac{1}{3x+9}-\frac{2}{x+3}=2\]?

Answer 2

ya thats one

Answer 3

you can subtract by writing
\[\frac{1}{3x+9}-\frac{2}{x+3}=\frac{1}{3x+9}-\frac{6}{3x+9}=\frac{-5}{3x+9}\]
then gett
\[\frac{-5}{3x+9}=2\iff -5=2(3x+9)\] and solve that one

Answer 4

-5=6x+18

Answer 5

\[-5=6x+18\]
\[x=-\frac{23}{6}\] which is what you got

Answer 6

yes but i don't know if it is
x=0,-2
x=0,2,-2
x=2,-2
x=0

Answer 7

it is none of those
maybe the question is different than the one you asked

Answer 8

those answers suggest that you have to solve a quadratic equation, which this one is not

Answer 9

oh okay ill try to figure it out