Can anyone help with this Ionization problem
N2 + E'
With a wavelength of 80.1

Question

Can anyone help with this Ionization problem
N2 + E' 
With a wavelength of 80.1

aaronq · Answer

whats the question?

anonymous · Answer

I need to find the ionization energy in kj/mol

aaronq · Answer

use plancks equation 

E=hc/lambda    

wavelength needs to be in meters in this equation

aaronq · Answer

it gives you energy in joules per photon.. so you need to multiply it by avogadros number and divide it by 1000 to go from Joules to kJ

anonymous · Answer

Im not sure how to do that

aaronq · Answer

which part?

aaronq · Answer

Energy = plancks constant x speed of light in vacuum/wavelength

anonymous · Answer

pretty much all of it:)

aaronq · Answer

look up those values on google

anonymous · Answer

I have planks constant how do I set up the equation

aaronq · Answer

the way i wrote it before?

anonymous · Answer

I am still lost I am pretty bad at chemistry

aaronq · Answer

this just math now,

the energy of one photon is equal to plancks constant multiplied by the speed of light (in vacuum) divided by the wavelengths (of the photon)

aaronq · Answer

wavelength*** not plural

anonymous · Answer

do i use speed of light in meters

aaronq · Answer

yes all in meters

anonymous · Answer

I have 6.626x10^-34 times 299,792,458 divided by 80.1
is this anywhere close

anonymous · Answer

I know the answer is 1495 kj/mol but still not setting up right
sorry I am very slow with this stuff

aaronq · Answer

80.1 what units is that in?  80 m wavelength photons won't ionize anything

anonymous · Answer

it is nanometers

aaronq · Answer

convert it to meters

anonymous · Answer

how do i do that?

aaronq · Answer

divide it by 1.0x10^9

anonymous · Answer

This is what I have 
8.01^10 J/6.626x10^-34 JS
then
1.384 x 10^-24/s
then 3.00 x 10^8 m/s divided by 1.384 x 10-24
is this anywhere close?

aaronq · Answer

why are you dividing by plancks constant...

set up the equation like this
$$E=\frac{ hc }{ \lambda } $$

anonymous · Answer

H= (6.26 x 10-34 Js) and C= (3.00 x  108 m/s)
divided by 8.01^10J 
Would i multiply H and C then divide my wavelength
does that look right

anonymous · Answer

or 6.626 for h

anonymous · Answer

c would be 10^8

aaronq · Answer

yes thats right


ps, speed of light, c, is not capitalized  .. capitalized C would be coulombs or capacitance.. or a bunch of other things

anonymous · Answer

Thank you for your help and patience

aaronq · Answer

no problem, don't forget to multiply by avogadros constant and divide by 1000