A skier of mass 40 kg, pushes off the top of a hill with an initial speed 4.0 m/s. Neglecting friction, how fast will she be moving after dropping 10 m in elevation?
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OpenStudy (anonymous):
is there any angle of inclination given???
OpenStudy (anonymous):
no
OpenStudy (anonymous):
i figure no friction means acceleration due to gravtiy which is almost 10m/s^2. So the skier has probably only been moving for about a second but idk because of the 4m/s
OpenStudy (anonymous):
so take it to be 0 degrees from the horizontal
OpenStudy (anonymous):
so vertical initial velocity is zero so apply v=u + at
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OpenStudy (anonymous):
what does the u represent?
OpenStudy (anonymous):
initial velocity = 0
OpenStudy (anonymous):
also there is no time. are we just assuming t= 1 because she has moved 10 m
OpenStudy (anonymous):
oh sorry use v^2 = u^2 + 2ah
OpenStudy (anonymous):
so it would be -14m/s correct?
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OpenStudy (anonymous):
or 14 m/s
OpenStudy (anonymous):
yup.... magnitude is 14
the sign just tells u d direction which is ur convention