expand the given logarithm and simplify
\[\log_{\sqrt{2}} (4x ^{3})\]
you can break up the product into a sum of logs with the same base sqrt(2)
i just looked at a video on youtube about this can i do it like this log√2(4x3)= log√2(4)+3log√2(x)
It may be wise to change bases - maybe Base 2 \(\log_{\sqrt{2}}(4x^{3}) = \dfrac{\log_{2}(4x^{3})}{\log_{2}(\sqrt{2})} = \dfrac{2 + 3\log_{2}(x)}{1/2} = 4 + 6\log_{2}(x)\) Just guessing. Various things mean "simplified" to various people.
3log√2(x)+4 this was supposed to be the answer
yeah you can do it as \[\log_{\sqrt2}(4)+\log_{\sqrt2}(x^3)\] \[=\log_{\sqrt2}(4)+3\log_{\sqrt{2}}(x)\]
then compute \[\log_{\sqrt2}(4)\]
how would i compute that if you could please explain it to me
anytime i have a number before the exponent and another number but after the log with the same log value i can just connect them?
It may be wise to change bases - maybe Base 2.
how can i change the base?
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