Question

You cross a pure breeding male with normal wings to a pure breeding wingless female. All of the F1 offspring have normal wings. Based on this result, which of the following statements is true:


The normal wing phenotype is dominant; the wingless phenotype is recessive.
The normal wing phenotype is recessive; the wingless phenotype is dominant.

Answer 1

Normal wing is dominant

Answer 2

i had that answer. just wanted to cross check to make sure i was right. thanks fo your help

Answer 3

You cross an F1 male to an F1 female (both phenotypically normal-winged). In their 400 offspring, you see a 3:1 ratio of normal to wingless. Upon closer examination, you find that all the wingless chickens are female. Based on these data:

i) Is the wingless gene autosomal or Z-linked?


Autosomal
Z-linked

Answer 4

Lets say x is winged and y is wingless.
birds have WZ instead of XY in humans
males are ZZ and females WZ
W does not contain genes

P1 is both purebred so homozygous
father is winged (ZxZx)
mother is wingless (WZy)

If you draw a punnett square of this you would find out that all females would be winged (WZx)
all males would be heterozygous winged (ZxZy) since x is dominant.

The P2 would be WZx + ZxZy
draw a square again
this time 50% of females would be wingless
all of the males would be winged

So it's z-linked

Answer 5

aww thanks