solve
how can you know such a thing?
i didn;t get u @satellite73
the best you could do is make the area a function of one side.
but only hypotenuese is given
I think they might want an answer in terms of the legs so in this right triangle: |dw:1365104034385:dw|
We know that a^2+b^2=82^2 so \[a=\sqrt{82^2-b^2}` and` b = \sqrt{82^2-a^a}\]
And of course a and b are the base and the height so Area = \[A=\frac{\sqrt{(6724-a^2)(6724-b^2}}{2}\]
i worked it out with my cousin and we got 810
yes ur right @123456man but how?
you only know the hypotenuse, you need the base and the height, and you do not have enough information
if the base and height are the same, then they are both \(41\sqrt{2}\) and so you can compute the area and get 1681
my cousin did most of the work after we argued about who was right.
but they don't have to be the same
the base could be \(1\) and the height could be \(\sqrt{81}\) for example
he flipped the triangle and used the cosine rule since the hypotenuse is known
then the area would only be \(\frac{\sqrt{81}}{2}\)
at the risk of repeating myself, there are infinitely many triangle with hypotenuse 82
What cosine rule did he use?
so his answer is wrong?
Not according to the asker.
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