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Physics 14 Online
OpenStudy (anonymous):

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_s11_qp_11.pdf Question 9 - Momentum

OpenStudy (kropot72):

A body of mass m, moving at velocity v, collides with a stationary body of the same mass and sticks to it. There will be a final common velocity. The conservation of momentum principle applies: \[m _{1}u _{1}+m _{2}u _{2}=(m _{1}+m _{2})v\] \[If\ m _{1}=m _{2},\ also\ u _{2}=0\] \[\mu _{1}=2mv\] \[v=\frac{u _{1}}{2}\] Therefore the final velocity will be half the initial velocity and the mass will be doubled. The final momentum is \[2m \times \frac{v}{2}=mv\] The final kinetic energy is found by doubling the mass and halving the velocity: \[Final\ kinetic\ energy=\frac{2m}{2}\times (\frac{v}{2})^{2}=\frac{1}{4}mv ^{2}\]

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