Question

x-2/3^7-2/3^8-2/3^9=1/3^9 then x=

Answer 1

can you clean that up, and use equation (repost)

Answer 2

well you can see that on left hand side (2/3 )^7 is common to all terms except x ..so take that common outside

Answer 3

*-(2/3)^7

Answer 4

can you do it ?

Answer 5

nooo, It is not (2/3)^7, but 2/3^7 , 2/(3)^7

Answer 6

still you can use the same logic take 2/(3&7)

Answer 7

can you use the equation below and rewrite it neatly?

Answer 8

2/3^7

Answer 9

\[x-(\frac{ 2 }{ 3 })^7-(\frac{ 2 }{ 3 })^8-(\frac{ 2 }{ 3 })^9=(\frac{ 1 }{ 3 })^9\]\[x-(\frac{ 2 }{ 3 })^{24}=(\frac{ 1 }{ 3 })^9\]\[x=(\frac{ 1 }{ 3 })^9+(\frac{ 2 }{ 3 })^{24}\]\[x=\frac{ 1+2^{24} }{ 3^{24 }}\approx5.94x10^-5\]

Answer 10

\[x-\frac{ 2 }{ 3^7 }\] guy all fractions are like this , got it?

Answer 11

\[x-\frac{ 2 }{ 3^7 }-\frac{ 2 }{ 3^8 }-\frac{ 2 }{ 3^9 }=\frac{ 1 }{ 3^9 }, then x= ??\]