Question

help ?

Answer 1

Q11: \[\sqrt{16*5}-3\sqrt{9*7}-\sqrt{25*5}-\sqrt{25*7}=4\sqrt{5}-9\sqrt{7}-5\sqrt{5}-5\sqrt{7}\]\[-\sqrt{5}-14\sqrt{7}\]The answer to Q11: A

Answer 2

@AriPotta

Answer 3

sorry, i can't really help. i'm trying to get my own work done lol. best of luck :]

Answer 4

Thanks

Answer 5

Q12:
\[\frac{ 4 }{ 6-\sqrt{7} }*\frac{ 6+\sqrt{7} }{ 6+\sqrt{7} }=\frac{ 4(6+\sqrt{7}) }{ 36-7 }\]\[\frac{ 24+4\sqrt{7} }{ 29 }\]The answer to Q12: B

Answer 6

Last one

Answer 7

@Lynncake

Answer 8

I can't give direct answers, but I can work with you through the answer.

Answer 9

ohkay

Answer 10

In this one \[\sqrt[8]{x^3}\]from the basic analysis that \[\sqrt[]{x}=\sqrt[2]{x}=x^{\frac{ 1 }{ 2 }}\]x is raised to the power of 1 (make it the numerator) and the 2 (make it the denominator)
Do you follow?

Answer 11

yeah

Answer 12

So what's the answer?