Question

physics help...
finding the area under a current-time graph

Answer 1

http://gyazo.com/5d5c3fd7a59d7e608a18f4dfb9764f47

Answer 2

@kropot72

Answer 3

its a graph of f(x)=1/x
Just integrate it with limits x=0 to x=15

Answer 4

This is a graph of a discharge of a capacitor which is an exponential.\[I=I _{0}e ^{-\frac{ t }{ RC }}\] R is the resistance (given) C is the capacitance.(not given). RxC = the time for the current to drop .3679 of it's max value. The area under an exponential function of the form
\[A _{0}e ^{-bx}\] is
\[A _{0}/b\] which may be found in any Calculus text. You need RC and the max current which you can get from the graph.

Answer 5

The question asks you to use the figure to determine the initial charge stored in the capacitor. You can find the area below the graph as follows:
Each division on the x-axis is 0.25 second. Each division on the y-axis is 0.025 mA.
To find the charge in the first 0.25 s multiply the average current by the time:
\[Q _{1}=I \times t=0.25\times 1.2\times 10^{-3}=0.3\ mC\]
Repeat this for each 0.25 s period and sum the results.