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OpenStudy (anonymous):
Find all solutions to the equation in the interval [0, 2 pi] -- 2cos(x) + sin(2x) = 0 ?? Please HELP!
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jimthompson5910 (jim_thompson5910):
use the identity sin(2x) = 2*sin(x)*cos(x)
jimthompson5910 (jim_thompson5910):
so 2cos(x) + sin(2x) = 0 turns into 2cos(x) + 2*sin(x)*cos(x) = 0
OpenStudy (anonymous):
thankyou (:
jimthompson5910 (jim_thompson5910):
then you factor out 2cos(x) to get 2cos(x) * (1 + sin(x)) = 0
jimthompson5910 (jim_thompson5910):
np
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