Question

Determine the concentration of a solution of sodium fluoride (NaF) that has a pH of 8.51 at 25C. I started calculating but got stuck.

Answer 1

this is what I have done:
The NaF dissociates into Na+ and F-, F- is the conjugate base of the acid HF, therefore, lookin up the Ka value for HF and dividing Kw by the Ka I get 1.41*10^-11.

Also, since the pH is 8.51, by subtracting 14-8.50 I get the pOH. Then, do 10^-5.49= 3.23*10^-6.
After this, I think I have to do an ice table, but I dont know how.