Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Given that D(x) = 2x, select all of the following that are true statements. a- D(x) is a function, b- xis the dependent variable, c- D(6) = 3, d- D(x) is a direct variation, e- D(x) is a rule for the set of points (5, 10), (6, 12) and (-2, -4).

jimthompson5910 (jim_thompson5910):

D(x) is a function ... true or false?

OpenStudy (anonymous):

A function is a relation in which each first coordinate in paired with exactly one second coordinate... So false?

jimthompson5910 (jim_thompson5910):

for any x you plug in, do you get a) exactly one output or b) more than one outputs

OpenStudy (anonymous):

b.

jimthompson5910 (jim_thompson5910):

so if you plugged in say x = 9, you would get more than one output?

jimthompson5910 (jim_thompson5910):

let's find out D(x) = 2x D(9) = 2*9 D(9) = 18 I only see one output, and it's 18

jimthompson5910 (jim_thompson5910):

this applies to any x value plugging in any x value gives you EXACTLY ONE output, so it's a function

OpenStudy (anonymous):

So A is one of the answers.

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

A is true

jimthompson5910 (jim_thompson5910):

x is the dependent variable...this is false since x is actually the independent variable

OpenStudy (anonymous):

So it cant be B.

jimthompson5910 (jim_thompson5910):

correct, how about C? is that true or false?

OpenStudy (anonymous):

false?

jimthompson5910 (jim_thompson5910):

correct, it's false

jimthompson5910 (jim_thompson5910):

how about d?

OpenStudy (anonymous):

Direct variation is a function of the form y=kx where k is not zero. So would that be true?

jimthompson5910 (jim_thompson5910):

yep, d is true

jimthompson5910 (jim_thompson5910):

how about e

OpenStudy (anonymous):

i dont know about e.

jimthompson5910 (jim_thompson5910):

well if you plug in x = 5, do you get y = 10?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!