4(r - 7/2)^2 - 40 19. Use the discriminant to find the number of unique real solutions. 20. Solve with the quadratic formula
u still want me to explan the first part or u understand wat i did?
Sorry, accidentally closed the other one. And no, I understand it. I looked over your steps. I just need help with the rest
wats the original equation again?
4r^2 - 28r = -49
the discriminant is b^ - 4ac
b^2 - 4ac
Yea, I know that
i can help u with number 20 but wat i do with number 19 is a guess :/
Any answer is better than mine, to be honest haha. I'm trying to finish this up because I'm not feeling well.
for number 19 wat i did was plug in values to get (-28)^2 - 4 (4) ( 48) and the answer u get is 0 which means that their r 0 real roots.
Alright, looks fine to me
lol that's my educated guess lol
Haha, like I said - any answer is better than mine.
so on to number 20, u know how to use the quadratic formula?
No clue :b
ok but u know wat the quadratic formula looks like right?
Yeah, some what
the discriminant is b^2+4ac
yea but how do u use it to prove the number of unique real solutions.
my gues was for number 19 wat i did was plug in values to get (-28)^2 - 4 (4) ( 48) and the answer u get is 0 which means that their r 0 real roots. do you know for sure how?
the quadratic formula is x = -b\[x=\frac{ -b \sqrt[\pm]{b ^{2}-4ac} }{ 2a }\]
What? haha
number 20! lol
I know I was reading it haha!
so wat u do is plug a= 4, b= -28, c= 49
Right
so work thst out and ur done with number 20 :P
Alrighty, thank you for all of your help. I would've been up all night, and I need to get rest for work tomorrow haha!
ok gn :)
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