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solve for X: square root x^2-x-5=5 A. -5 B. -6 C. 6 D. -5,6
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the square root is over whole problem
@jim_thompson5910
do you mean \[\sqrt{x^2-x-5} = 5\]
yep
so how would I go about solving it?
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I got -5
\[\large \sqrt{x^2-x-5} = 5\] \[\large x^2-x-5 = 5^2\] \[\large x^2-x-5 = 25\] \[\large x^2-x-5 - 25 = 0\] \[\large x^2-x-30 = 0\]
I'll let you finish
yep I got my answer -5 that right?
\[\large x^2-x-30 = 0\] \[\large (x+5)(x-6) = 0\]
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-5.6 is the answer?
better, it's 6, -5 or -5, 6
sorry haha that what I ment t type lol
that's fine
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