Question

write the equation of a circle with its center at (5,-1)and radius 6

Answer 1

Formula for a circle with centre (xo, yo) and radius r is:

(x - xo)2 + (y - yo)2 = r2

Circle centre (0, 0) and radius 14:

(x - 0)2 + (y - 0)2 = 142

x2 + y2 = 196

Answer 2

A. (x+5)-(y-1)^2=6
B. (x-5)^2+(y+1)^2=36
C. (x-5)^2+(y-1)^2=36
D. (x+5)^2+(y-1)^2=6 @50_cent

Answer 3

D

Answer 4

how'd you get that?

Answer 5

idk I do my homework

Answer 6

I don't cheat

Answer 7

give me best response

Answer 8

what? all I wanna know is the work for it so that I can understand it

Answer 9

go to youtube.com

Answer 10

let's start with the center radius equation of the circle as @50_cent gave
\[(x-x_0)^2+(y-y_0)^2=r^2\]
the center is \((x_0,y_0)\) and the radius is \(r\)

what is the value of \(x_0,y_0, \text{ and } r\) the problem?

Answer 11

x=5 y =1 r = 6. would it be C.?

Answer 12

almost.
its x0 = 5, y0 = -1, and r = 6.

now, sub these values into the equation, and you'll have the answer to your question.

Answer 13

I got B. (x-5)^2+(y-1)^2=36

Answer 14

y-(-1) = y + 1
the correct answer is B.