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Algebra
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what is 3^(-2)-2? and 3^(-1)-2
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\[\frac{ 1 }{ 3^{2} }-2\] \[\frac{ 1 }{ 9 }-\frac{ 18 }{ 9 }=\frac{ -17 }{ 9 }\]
remember the exponential rule \[a^{-m}={1\over a^m}\]
thank you
Since its raised to a negative it should become: \[\frac{ 1 }{ 3^2 }-2\]
a negative exponent is called a "reciprocal"
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you can figure out the second one using the rule electrokid just mentioned
yes thank you @electrokid
Yeah @electrokid gave you a great 'definition' from which you can work thorough the next problem.
thanks
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