Question

What is the joint probability P(x>y)of F(x,y)=xy where 0<=x<=2 and 0<=y<=1???
I keep getting 1/8 while the answer key says 7/8

Answer 1

correct me if i am wrong, but do you compute via
\[\int_0^1\int _0^x xydxdy\]?

Answer 2

Yes

Answer 3

wait no

Answer 4

dydx.. I think

Answer 5

yeah that would make more sense

Answer 6

hmm in that case you do get \(\frac{1}{8}\) don't you?
i wonder why it is wrong

Answer 7

it is \(P(X>Y)\) right? not the other way around

Answer 8

Okay, imma go with my gut. I guess the answer key is wrong.
Thank You

Answer 9

hello joe!!!

Answer 10

Your sample space looks like this: So your integration limits should be:\[\int\limits_{0}^1\int\limits_{y}^2xydxdy\]i think.