Mathematics
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OpenStudy (anonymous):
Solve x^2=6x-11
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OpenStudy (anonymous):
try to put all the terms on one side, remember that when moving a term to the other side, we change its sign.
OpenStudy (anonymous):
Example: x^2 = 5x + 6.
We will have: x^2 - 5x -6 = 0.
OpenStudy (anonymous):
Then, use the quadratic formula.
OpenStudy (anonymous):
\[x = \frac{ - b +/-\sqrt{b^2 - 4ac} }{ 2a }\]
OpenStudy (anonymous):
\[3+2\sqrt{5}\]\[3+i\sqrt{2}\]\[3-2\sqrt{5}\]\[3-i \sqrt{2}\] these are the options
there is more than one correct anwser.
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OpenStudy (aravindg):
well as violy said above use the quadratic formula once you get all terms to one side ..Tell us what you get ?
OpenStudy (anonymous):
\[3+/-\sqrt{-3^2-22}\]
thats what i got
OpenStudy (aravindg):
how did you get that ?
OpenStudy (anonymous):
Quadratic equation
OpenStudy (anonymous):
try to identify a, b and c first when you arrived in the form: ax^2+bx + c =0.
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OpenStudy (aravindg):
yep ..can you show how you substituted the terms ?
OpenStudy (anonymous):
careful on plugging-in the values on the quadratic formula..
OpenStudy (anonymous):
a=1 b=-6 and c=11
OpenStudy (aravindg):
thats right !!
OpenStudy (aravindg):
now substitute in quadratic equation
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OpenStudy (aravindg):
-b=?
b^2=?
4ac= ?
OpenStudy (aravindg):
2a= ?
OpenStudy (anonymous):
i did and then i got stuck on simpflying
6
-6^2
4(1)(11)=44
2(1)=2
OpenStudy (aravindg):
ya that is right !
OpenStudy (aravindg):
now just do operations like additions,subtraction and division
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OpenStudy (aravindg):
tell me how the numerator will be ?
OpenStudy (anonymous):
i dont know
OpenStudy (aravindg):
why not ?just put it there!!
OpenStudy (aravindg):
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