Medal given to person who answers! Find the area of a sector of a circle with radius 12 and arc length 10(pi). Show work
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
|dw:1365192409384:dw|Ok for this one is is easiest to draw it out first.
OpenStudy (anonymous):
|dw:1365192545644:dw|
OpenStudy (anonymous):
That is the final answer?
OpenStudy (anonymous):
No, right?
OpenStudy (anonymous):
Like what are the steps?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
No that isn't the answer.. You have to plug in the information they have given you.
The r in this formula represents 12, the radius. While m represents the measure of the length they gave you, 10pi.
OpenStudy (anonymous):
So:\[144 \left( 10\pi \right) \over 360\]
OpenStudy (anonymous):
1440pi over 360?
OpenStudy (anonymous):
a=pir^2*10pi/2pir=5pir
OpenStudy (anonymous):
Could someone just write out the entire answer so that i can understand the steps easier? Thanks
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@Emah Could you help?
OpenStudy (anonymous):
A=pi r^2/2 pi r*10 pi=5 pi r=5 pi 12=60 pi
OpenStudy (anonymous):
Sorry but im not following..Maybe make it easier to read?
OpenStudy (anonymous):
I'm sorry, I know how to do this, but I can't figure out the 10pi being the measure.. Usually its a degree..
OpenStudy (anonymous):
A=(πr^2)/2πr*10π=5πr=5π*12=60π
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
does the / mean a fraction like (pi)(r)^2 over something else?