Question

36y^2-84y-147

Answer 1

Do you need to factor this trinomial?

Answer 2

yes

Answer 3

First, factor a common factor out of all three terms. Do you see a common factor?

Answer 4

i dont even know how to do this. so can you just give me the answer?

Answer 5

Let's go over it step by step.
First step, factor a common factor: 36, -84, and -14 have a common factor of 2, so let's factor that out:
36y^2 - 84y - 14
2(18y^2 - 42y - 7)

Answer 6

Now we need to factor 18y^2 - 42y - 7
First we multiply 18 and -7 together and we get -126

Answer 7

Now we need two factors of -126 that multiply to -42

Answer 8

@alexis_kathleen based on the Code of Conduct of this website, it is not right to give out the answer. It is not right, and the user does not learn anything.
@mathstudent55 good job, in not just giving him the answer, and showing him step by step :)

Answer 9

Thanks.
Let's start from the beginning. I misread the problem. The last number is 147. I thought it was 14 followed by a question mark.

Answer 10

Let's factor 36y^2 - 84y - 147
The three terms do not have any common factors, so we begin by multiplying 36
and -147

Answer 11

36 * (-147) = -5292

Answer 12

The numbers are -126 and 42, since -126 * 42 = -5292, and
-126 + 42 = -84
Now we break up the middle term into two parts using these two numbers.
36y^2 - 84y - 147 =
36y^2 - 126y + 42y - 147
Now we factor by parts. Take a common factor out of the first two terms and take a common factor out of the last two terms.
18y(2y - 7) + 21(2y - 7) =
(2y - 7)(18y + 21)
Now I see that 18y + 21 has a common factor of 3, so we can factor that out:
3(6y + 7)(2y - 7)