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OpenStudy (anonymous):
find the value of the annuity.
a1=$7000 I=0.10 n=5
13 years ago
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OpenStudy (anonymous):
@jim_thompson5910 I followed the steps but when it comes to finding the value I dont get it.
This is where I have gotten so far.
\[7000\frac{ (1 + 0.10)^5 - 1 }{ 0.10 }\]
13 years ago
jimthompson5910 (jim_thompson5910):
assuming you're using the correct formula
13 years ago
OpenStudy (anonymous):
\[this is the formula I was told \to use: Sn = a1( \frac{ (1 + I)^n -1 }{ I })\]
13 years ago
jimthompson5910 (jim_thompson5910):
\[\large 7000\frac{ (1 + 0.10)^5 - 1 }{ 0.10 }\]
\[\large 7000\frac{ (1.10)^5 - 1 }{ 0.10 }\]
\[\large 7000\frac{1.61051 - 1 }{ 0.10 }\]
\[\large 7000\frac{0.61051 }{ 0.10 }\]
\[\large 7000*6.1051\]
\[\large 42,735.70\]
13 years ago
OpenStudy (anonymous):
oh and round to the nearest cent
13 years ago
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jimthompson5910 (jim_thompson5910):
I think that's right. Does it say anything about when it's compounded?
13 years ago
OpenStudy (anonymous):
No it doesn't.
13 years ago
jimthompson5910 (jim_thompson5910):
alright
13 years ago
jimthompson5910 (jim_thompson5910):
oh and does it say anything about monthly payments?
13 years ago
OpenStudy (anonymous):
No it does not. The answer you gave me is correct. I just checked it :)
13 years ago
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jimthompson5910 (jim_thompson5910):
oh, just checking
not very good with finance problems lol
13 years ago
jimthompson5910 (jim_thompson5910):
but glad it works out
13 years ago
OpenStudy (anonymous):
You've helped me so much though!!
13 years ago
jimthompson5910 (jim_thompson5910):
glad to be of help
13 years ago
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