a positive integer m divides 748x+714y for all values of x and y .how many values of m can we have ?
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OpenStudy (anonymous):
linear combination of 748 and 714
OpenStudy (anonymous):
:O , i didnt understand
OpenStudy (anonymous):
4 values of m
OpenStudy (anonymous):
can u explain how you got this?
OpenStudy (anonymous):
what is the answer?
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OpenStudy (anonymous):
i dont know but the options are :-
1)2
2)3
3)4
4) infinitely many
OpenStudy (anonymous):
748x+714y=748(1)+(-1)714
OpenStudy (anonymous):
m can be 1,2,17,34
OpenStudy (anonymous):
firstly note that the greatest common divisor of 748 and 714 is 34 because:
\[748=2^2*11*17\]\[714=2*3*7*17\]now we know that m divides\[34(22x+21y)\]for all values of x and y specially for x=1 and y=-1 which will gives the number as\[34(22-21)=34\]so m must be a divisor of 34 and since we know 34=2*17 so\[m=1,2,17,34\]
OpenStudy (anonymous):
we let x=1 and y=-1 because we want to make the 22x+21y equal to 1
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