Question

Helpppp ive asked a lot of people

Answer 1

What is the problem?

Answer 2

\[\log_{3} x= \log_{1/3} (x)+8\]

Answer 3

@hedyeh99

Answer 4

Oooh, I am not good with log, but i suggest you use wolfram alpha, it can do log, it is amazing

Answer 5

i just found it hey how can i put the 1/3 at the bottom it keeps showing as a 1/3x
een if i use parenthese

Answer 6

parenthesis

Answer 7

you can do a change of base to avoid confision

Answer 8

\[
\ln_{1/3}(x)=\frac{\ln_3(x)}{\ln_3(1/3)}
\]

Answer 9

If this is right, your answer is infinity, but I'm not sure
http://www.wolframalpha.com/input/?i=log3%28x%29%3Dlog1%2F3%28x%29%2B8
Could you please see if infinity is correct? @electrokid

Answer 10

(** sorry for confusion with the ln **)
so, what you now have is:
\[
\log_3(x)=\frac{\log_3(x)}{\log_3(1/3)}+8\\
\quad=\frac{\log_3(x)}{-\log_3(3)}+8\\
\quad=-\log_3(x)+8\qquad\qquad\text{(since }\log_3(3)=1
\]

Answer 11

@hedyeh99 @charliem07 kapeesh?

Answer 12

x is supposed to equal 81

Answer 13

i looked at the back but i would like to know how ..

Answer 14

I'll let you take over @electrokid because I don't really know log

Answer 15

continue;;;
\[
\log_3(x)=-\log_3(x)+8\\
\implies2\log_3(x)=8\\
\implies\log_3(x^2)=8\\
\text{now take antilog -> exponent to "3"}\\
x^2=3^8\\
x=\pm 3^4\qquad\qquad\text{note: x>0}\\
x = 3^4\\
\color{red}{\large\boxed{x=81}}
\]

Answer 16

follow?

Answer 17

there is one basic rule when you see an equation with "log(x)"
try to get all the "x" under one log with the same base.

Answer 18

@charliem07 knock, knock

Answer 19

im reading it trying to figure it out lol.. .. i was stuck on the fraction part... now i see how you got it out by taking out the minus...

Answer 20

yea its so much easier to understandd now thats what i wanted the same base but i had no clue what to do wit htat fraction.

Answer 21

that step involves the following details:
\[\log_3(1/3)=\log_3(3^{-1})=-\log_3(3)\]

Answer 22

OHHHHHHHHH!!!!!! OKAY that helps i never saw it like that but it makes a lot of sense

Answer 23

that way or if you do not remember the reciprocal, then this way gets you to the same place
\[\log_3(1/3)=\log_3(1)-\log_3(3)=0-\log_3(3)\]
since the logarithm of "1" to any base is "0"

Answer 24

yes..... how about when you have the natural log... several times in parenthesis

Answer 25

ln(ln(x)) = 3

Answer 26

isnt the ln automatically ln10

Answer 27

go step by step.
remember that \(\ln\equiv\log_e\)

Answer 28

\[\ln(\ln(x))=3\\
\ln(x)=e^3\\
x=e^{e^3}
\]

Answer 29

how does that distribute or how does that work
i know ln(e)

Answer 30

but how did you raise the e^3