1. In the function, A(t)=4(1/2)^1/5t A(t) represents the: initial amount of the substance growth factor number of times to complete a cycle amount of the substance present at time t 2. In the function, M(t)=8(2)^1/6t 6 represents the: initial amount of the substance growth factor number of times to complete a cycle amount of the substance present at time t
Did that help? it appears there is two of you working on this
Not really :(
I think I'm a bit more behind than she is
at an initial amount what is the time?
amount of the substance present at time t ?
alright i'll use the same analogy. If you had 3 gummy bears at first before doing anything (meaning the time was 0) and then you gave 2 gummy bears an hour later (t=1), what is another name for when you had 3 gummy bears
Initial time
yes that would be the initial time but what would the gummy bears be
initial amount
yes so if A(t)= is the amount at time t, then A(0) will give you the initial amount of substance correct?
so if you plug in t=0 to the equation then what do you get for an answer
0?
\[A(0)=4(\frac{1}{2})^{\frac{1}{5}*0}=4(\frac{1}{2})^0\] what is anything to the zero power
\[(\frac{1}{2})^0=?\]
1?
yes so if that part is one then it's \[A(0)=4*1=4\]
so it's saying that the amount at t =0 is 4, which just so happens to be what is in your function.
so what does that mean that 4 is within the equation
oops i'm sorry i thought they were the same question... but i gave you the answer for the first question A(t) is read as a "Function of time" , Amount of someting is a function therefore Amount of substance in terms of time
or A(t) is the amount of substance at time t
In that case would the second question be number of times to complete a cycle?
for question two, is that suppose to be what does 1/6 mean
yes i believe so
Thanks
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