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Mathematics 18 Online
OpenStudy (anonymous):

convert

OpenStudy (anonymous):

|dw:1365273085804:dw|

OpenStudy (anonymous):

The number 125.3? And you're meant to write it as the quotient of two integers?

OpenStudy (anonymous):

i think @SmoothMath , u r not familiar with this question

OpenStudy (anonymous):

I'm asking for clarification.

OpenStudy (anonymous):

I think its supposed to convert to an irrational number, p/q, since it has a little line over the 3.

OpenStudy (anonymous):

yes @some_someone

OpenStudy (anonymous):

There's no such thing as "converting to an irrational number." A number is either rational or irrational.

OpenStudy (anonymous):

ok this number is irrational, @SmoothMath , but its in decimal, so he wants to convert it to p/q

OpenStudy (anonymous):

This number is rational though, so we can express it as the quotient of two numbers p and q, where p and q are integers.

OpenStudy (anonymous):

It's rational, @some_someone

OpenStudy (anonymous):

If it was irrational, then by definition, you could not write it as p/q, at least assuming p and q were integers.

OpenStudy (anonymous):

okaii then, @SmoothMath , then explain to him how to express it as the quotient of two numbers p and q, where p and q are integers.

OpenStudy (anonymous):

Exactly, so this is a repeating decimal, which means it can be written as a fraction. Do you know what the fraction 0.3333... is?

OpenStudy (anonymous):

\[\Large 0.\bar3 = \frac{1}{3}\]

OpenStudy (anonymous):

@SmoothMath , you are correct, repeating decimals are rational

OpenStudy (anonymous):

|dw:1365274281716:dw|

OpenStudy (anonymous):

Interesting approach. You still need for P and Q to be integers though.

OpenStudy (anonymous):

In your answer, P = 11279.7 is not an integer.

OpenStudy (anonymous):

so, in question there is also written p and q are integers and q is not equal to 0

OpenStudy (anonymous):

Exactly. I think this approach might be simpler for you to work with: \[\Large0.\bar3 = \frac{1}{3}\] therefore, \[\Large125.\bar3 = 125 + \frac{1}{3}\]

OpenStudy (anonymous):

Does that much make sense to you?

OpenStudy (anonymous):

|dw:1365319852545:dw| @SmoothMath and @some_someone

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