Question

Solve the equation on the interval [0,2pi): 12cos^2x-9=0

Answer 1

well start by rewriting the equation

\[12\cos^2(x) = 9\]

divide both sides by 12

\[\cos^2(x) = \frac{9}{12}\]

simplify the fraction and then take the square root of both sides...

this will result in 2 answers for cos(x) positive and negative.

Which means you will have 4 answers as answers on your given domain.

Answer 2

Thanks for the help I got my 4 answers.