Question

1. If ∠D = 28° and arc TE = 24°, what is the measure of arc TF?
2. If ∠D = 50° and arc TF = 120°, what is the measure of arc TE?

Answer 1

@wio

Answer 2

@jim_thompson5910

Answer 3

now you are using the last theorem on this page

http://www.regentsprep.org/Regents/math/geometry/GP15/CircleAngles.htm

Answer 4

i don't get it. i'm not getting the right answers @jim_thompson5910

Answer 5

The theorem says that

angle D = (TF - TE)/2

Answer 6

d=(tf-24)/2

Answer 7

d=(tf-24)/2

28=(tf-24)/2

28=(x-24)/2

solve for x

Answer 8

do I add 24 to both sides?

Answer 9

28=(x-24)/2

28*2=x-24

Answer 10

56=x-24
x=80?

Answer 11

good

Answer 12

you're doing slightly the same for the second one

Answer 13

okay so d=(te-120)/2 ?

Answer 14

tf - te

not te - tf

Answer 15

why did it change this time?

Answer 16

it's always been TF - TE

Answer 17

oh wait, you're right.
d=(120-TE)/2

Answer 18

50=(120-TE)/2
100=120-TE
-120 -120
-20=-TE
20=TE
is this right?

Answer 19

@jim_thompson5910

Answer 20

one sec

Answer 21

good, TE = 20