MIT 6.002 Circuits and Electronics, Spring 2007
22 Online
OpenStudy (anonymous):
please help h4p2 mit 6.002 how find vo in p2
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OpenStudy (nurali):
\[vo=\frac{ Vi(R _{L}) }{ R _{L}+R _{i n} }\]
OpenStudy (anonymous):
thanks! but in part second when zener diode place in circuit how to find VO & vo?
OpenStudy (nurali):
\[c-V _{o}=\frac{ V _{1}(R _{L}) }{ R _{L}+R _{i n}}\]
\[d-v _{o}=\frac{ V _{i}(R _{L}) }{ R _{L}+R _{i n}}\]
OpenStudy (anonymous):
thanks and last Q RL ?
OpenStudy (anonymous):
plz give me formula for this RL
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OpenStudy (nurali):
\[V _{o}=V _{i}*\frac{ R _{L _{\min}} }{ R _{L _{\min}}+R _{IN} }\]
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
plz explain RLmin
OpenStudy (anonymous):
sajid have u done h3p4
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
can u tell me answers of h3p2 and h3p4 d1 and d2 only
OpenStudy (anonymous):
0.000182 D1
0.00024 D2
OpenStudy (anonymous):
It is for h3p4
OpenStudy (anonymous):
but it says wrong
OpenStudy (anonymous):
what is your v1 , v2 and R value?
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OpenStudy (anonymous):
v1=2,,v2=3,,r=4.7
OpenStudy (anonymous):
wait
OpenStudy (anonymous):
waiting ....thanks
OpenStudy (anonymous):
check this
D1= 0.74
D2= 1.59
OpenStudy (anonymous):
sorry bro still wrong
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OpenStudy (anonymous):
WHAT IS your peak voltage
OpenStudy (anonymous):
10
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
i put it 7.5 b/c it is mine
OpenStudy (anonymous):
okayy...
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OpenStudy (anonymous):
now check this
D1=1.277
OpenStudy (anonymous):
sorry still wrong
OpenStudy (anonymous):
d2=0.85
OpenStudy (anonymous):
1 min
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
D1=0.0012 it will be correct i am sure
OpenStudy (anonymous):
check it
OpenStudy (anonymous):
really sorry bro still wrong
OpenStudy (anonymous):
r u sure abt ur v1,v2,r and vs values?
OpenStudy (anonymous):
yes
v1=2...v2=3...r=4.7...
What is the maximum positive voltage (in Volts) that can appear at v?
ans=2
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OpenStudy (anonymous):
What is the minimum (negative) voltage (in Volts) that can appear at v?
ans=-3 correct
OpenStudy (anonymous):
and peak vlatage i.e vs ??
OpenStudy (anonymous):
10.0
OpenStudy (anonymous):
and R = 4.7K ?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
D1=0.00127 BRO this the answer if still u have problem then i will give u formula solve it for urself
OpenStudy (anonymous):
great right answer and d2 <give me formula>
thanks alot
really thanks
OpenStudy (anonymous):
ok wait
OpenStudy (anonymous):
d2= 0.000851
OpenStudy (anonymous):
bingo great
thanks alot
thanks...
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OpenStudy (anonymous):
now plz clik on best response
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
bye thanks again
OpenStudy (anonymous):
u welcom