Question

simplify (2√5+3√7)^2 show steps

Answer 1

pls i really need help

Answer 2

on simplifying just like (a+b)^2 = a^2+2ab +b^2
we get
40+2*2*3*\[\sqrt{35}\]+63
=103+6*square root of (35)

Answer 3

\[(2\sqrt{5}+3\sqrt{7})(2\sqrt{5}+3\sqrt{7})\]

Answer 4

so lost o.o

Answer 5

\[4\sqrt{25}+6\sqrt{35}+6\sqrt{35}+9\sqrt{49}\]

Answer 6

could you explain in like steps?

Answer 7

When it is squared, that means that you multiply it by itself, like \[4^{2}= 4\times4\]

Answer 8

Ok,(2\sqrt{5}+3\sqrt{7})(2\sqrt{5}+3\sqrt{7})

Answer 9

Oh,oops

Answer 10

That looks a little confusing

Answer 11

very lol

Answer 12

Here is a video to help you https://www.khanacademy.org/math/algebra/polynomials/multiplying_polynomials/v/multiplying-binomials

Answer 13

If you do not get it, I will try to explain

Answer 14

how does it help me simplify

Answer 15

It will show you how to simplify

Answer 16

ok

Answer 17

(a+b)^2=a^2+2*a*b +b^2

Answer 18

\[(2\sqrt{5} + 3\sqrt{7})^{2}\]
\[(2\sqrt{5} + 3\sqrt{7}) (2\sqrt{5} + 3\sqrt{7})\]
Because \[(a+b)^{2} = a^{2} + 2(a)(b) + b^{2}\]
Therefore\[(2\sqrt{5} + 3\sqrt{7}) (2\sqrt{5} + 3\sqrt{7}) = 20 + 6\sqrt{35} + 63\]
Therefore \[6\sqrt{35} +83\]

Answer 19

omg that's all i wanted thank you sooo much XD

Answer 20

Your welcome :)

Answer 21

@PinkPanda me??

Answer 22

yesh

Answer 23

@PinkPanda No problem ^.^

Answer 24

wait did you mean 83 or 43?

Answer 25

I meant 83

Answer 26

so you subtracted 20 from each side?

Answer 27

@BABYShawol184

Answer 28

No I multiplied the two binomials which gave me the answer
\[20 + 6\sqrt{35} +83\]
Then I simplified by adding 20 and 83 which gave me 83

Answer 29

oh ok lol

Answer 30

Does that help??? :S